Mechanical reformat — no logic changes. 398 files changed, 19125 insertions(+), 16457 deletions(-). Prettier 3.8.4 with .prettierrc (singleQuote:true, semi:true, tabWidth:2, trailingComma:all, printWidth:100). Isolated per D-13-08 for reviewability.
123 lines
4.2 KiB
TypeScript
123 lines
4.2 KiB
TypeScript
/**
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* Unit tests for rank.ts — fractional-indexing helpers (D-13).
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*
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* Pure function tests, no DB needed.
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* Run: pnpm --filter @familysync/api exec vitest run tests/lib/rank.test.ts
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*/
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import { describe, it, expect } from 'vitest';
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import { rankForAppend, rankBetween } from '../../src/lib/rank.js';
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describe('rankForAppend', () => {
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it('returns "a0" when list is empty (no existing rank)', () => {
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const rank = rankForAppend(null);
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expect(rank).toBe('a0');
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});
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it('returns a rank string that sorts AFTER the given last rank', () => {
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const lastRank = 'a0';
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const newRank = rankForAppend(lastRank);
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expect(newRank > lastRank).toBe(true);
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});
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it('multiple appends produce strictly increasing ranks', () => {
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let last: string | null = null;
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const ranks: string[] = [];
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for (let i = 0; i < 5; i++) {
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const r = rankForAppend(last);
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ranks.push(r);
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last = r;
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}
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// Each successive rank must be greater than the previous
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for (let i = 1; i < ranks.length; i++) {
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expect(ranks[i] > ranks[i - 1]).toBe(true);
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}
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});
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});
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describe('rankBetween', () => {
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it('returns "a0" when both prev and next are null (empty list)', () => {
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const rank = rankBetween(null, null);
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expect(rank).toBe('a0');
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});
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it('returns a rank that sorts between two existing ranks', () => {
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const first = rankForAppend(null); // 'a0'
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const second = rankForAppend(first); // 'a1'
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const between = rankBetween(first, second);
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expect(between > first).toBe(true);
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expect(between < second).toBe(true);
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});
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it('returns a rank that sorts AFTER prev when next is null', () => {
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const prev = 'a0';
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const rank = rankBetween(prev, null);
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expect(rank > prev).toBe(true);
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});
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it('returns a rank that sorts BEFORE next when prev is null', () => {
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const next = 'a1';
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const rank = rankBetween(null, next);
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expect(rank < next).toBe(true);
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});
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it('produces lexicographically stable ordering across multiple insertions', () => {
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// Simulate inserting between 'a0' and 'a1' repeatedly
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const a = 'a0';
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const b = 'a1';
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const c = rankBetween(a, b);
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const d = rankBetween(a, c);
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const e = rankBetween(c, b);
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// All four ranks should be orderable
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expect(a < d).toBe(true);
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expect(d < c).toBe(true);
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expect(c < e).toBe(true);
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expect(e < b).toBe(true);
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});
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/**
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* Precision regression test — LIST-03, Pitfall 2.
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*
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* Repeated "zipper" inserts (always between the first two items) must produce
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* strictly increasing, unique, non-empty rank strings across many iterations.
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* Float-based approaches would exhaust precision around iteration 52; the
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* fractional-indexing string approach degrades gracefully by growing string
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* length instead.
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*/
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it('repeated mid-point inserts produce unique strictly-increasing ranks over 100 iterations (precision — Pitfall 2)', () => {
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const ranks: string[] = [rankBetween(null, null), rankBetween(null, null)];
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// Set up: two items with known ranks
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ranks[0] = rankBetween(null, null); // 'a0'
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ranks[1] = rankBetween(ranks[0], null); // 'a1'
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// Insert 100 times between the first item and the second item
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// This is the worst-case "zipper" pattern — always inserting at the same gap
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for (let i = 0; i < 100; i++) {
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const newRank = rankBetween(ranks[0], ranks[1]);
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// Must be strictly between
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expect(newRank > ranks[0]).toBe(true);
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expect(newRank < ranks[1]).toBe(true);
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// Must be a non-empty string
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expect(newRank.length).toBeGreaterThan(0);
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// Must be unique (not equal to any existing rank)
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expect(ranks).not.toContain(newRank);
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// New item goes at index 1 (after first, before old second) — shift old items
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ranks.splice(1, 0, newRank);
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}
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// Verify the final list is fully sorted ASC
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for (let i = 1; i < ranks.length; i++) {
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expect(ranks[i] > ranks[i - 1]).toBe(true);
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}
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});
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it('rank between two neighbors is strictly between them (D-13 reorder contract)', () => {
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const prev = 'a0';
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const next = 'a3';
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const middle = rankBetween(prev, next);
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expect(middle > prev).toBe(true);
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expect(middle < next).toBe(true);
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});
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});
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